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DOI: 10.24193/subbmath.2018.4.06

Sufficient conditions of boundedness of L-index and analog of Hayman’s Theorem for analytic functions in a ball

Andriy Bandura and Oleh Skaskiv

Abstract. We generalize some criteria of boundedness ofL-index in joint variables for analytic in an unit ball functions. Our propositions give an estimate maximum modulus of the analytic function on a skeleton in polydisc with the larger radii by maximum modulus on a skeleton in the polydisc with the lesser radii. An analog of Hayman’s Theorem for the functions is obtained. Also we established a connection between class of analytic in ball functions of boundedlj-index in every direction 1j, j ∈ {1, . . . , n} and class of analytic in ball of functions of boundedL-index in joint variables, whereL(z) = (l1(z), . . . , ln(z)), lj:Bn→R+ is continuous function,1j= (0, . . . ,0, 1

|{z}

j−th place

,0, . . . ,0)∈Rn+, z∈Cn.

Mathematics Subject Classification (2010):32A05, 32A10, 32A30, 32A40, 30H99.

Keywords:Analytic function, unit ball, boundedL-index in joint variables, max- imum modulus, partial derivative, boundedL-index in direction.

1. Introduction

Recently, there was introduced a concept of analytic function in a ball in Cn of bounded L-index in joint variables [8]. We also obtained criterion of boundedness of L-index in joint variables which describes a local behavior of partial derivatives on a skeleton in the polydisc and established other important properties of analytic functions in a ball of bounded L-index in joint variables. Those investigations used an idea of exhaustion of a ball inCn by polydiscs.

The presented paper is a continuation of our investigations from [8]. We set the goal to prove new analogues of criteria of boundedness ofL-index in joint variables for analytic in a ball functions. Particular, we prove an estimate of maximum modulus on a greater polydisc by maximum modulus on a lesser polydisc (Theorems 3.1, 3.2) and obtain an analog of Hayman’s Theorem for analytic functions in a ball of bounded

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L-index in joint variables (Theorems 4.1 and 4.2). For entire functions similar propo- sitions were obtained by A. I. Bandura, M. T. Bordulyak, O. B. Skaskiv [4, 5] in a case L(z) = (l1(z), . . . , ln(z)), z∈Cn.Also A. I. Bandura, N.V. Petrechko, O. B. Skaskiv [6, 7] deduced same results for analytic in a polydisc functions. Hayman’s Theorem and its generalizations for different classes of analytic functions [1, 3, 5, 7, 12, 15, 20, 21]

are very important in theory of functions of bounded index. The criterion is helpful [1, 9] to investigate boundedness of index of entire solutions of ordinary or partial differential equations.

Note that the corresponding theorems for entire functions of bounded l-index and of boundedL-index in direction were also applied to investigate infinite products (see bibliography in [21, 1]). Thus, those generalizations for analytic in a ball functions are necessary to study L-index in joint variables of analytic solutions of PDE’s, its systems and multidimensional counterparts of Blaschke products. At the end of the paper, we present a scheme of application of Hayman’s Theorem to study properties of analytic solutions in the unit ball.

2. Main definitions and notations

We need some standard notations. Denote R+= (0,+∞),0= (0, . . . ,0), 1= (1, . . . ,1), 1j= (0, . . . ,0, 1

|{z}

j−th place

,0, . . . ,0)∈Rn+,

R= (r1, . . . , rn)∈Rn+, z= (z1, . . . , zn)∈Cn,|z|=q Pn

j=1|zj|2.

ForA= (a1, . . . , an)∈Rn, B= (b1, . . . , bn)∈Rn we will use formal notations without violation of the existence of these expressions

AB= (a1b1,· · · , anbn), A/B= (a1/b1, . . . , an/bn), AB =ab11ab22·. . .·abnn, kAk=a1+· · ·+an,

and the notation A < B means that aj < bj, j ∈ {1, . . . , n}; the relation A ≤ B is defined similarly. For K = (k1, . . . , kn) ∈ Zn+ denote K! = k1!·. . . ·kn!. The polydisc{z∈Cn : |zj−zj0|< rj, j= 1, . . . , n}is denoted by Dn(z0, R),its skeleton {z ∈ Cn : |zj −z0j| = rj, j = 1, . . . , n} is denoted by Tn(z0, R), and the closed polydisc {z ∈ Cn : |zj −z0j| ≤ rj, j = 1, . . . , n} is denoted by Dn[z0, R]. The open ball{z ∈Cn : |z−z0|< r} is denoted by Bn(z0, r),its boundary is a sphere Sn(z0, r) ={z∈Cn : |z−z0|=r},the closed ball{z∈Cn : |z−z0| ≤r}is denoted byBn[z0, r],Bn =Bn(0,1),D=B1={z∈C: |z|<1}.

For K = (k1, . . . , kn) ∈ Zn+ and the partial derivatives of an analytic in Bn functionF(z) =F(z1, . . . , zn) we use the notation

F(K)(z) =∂kKkF

∂zK = ∂k1+···+knF

∂zk11. . . ∂znkn

.

Let L(z) = (l1(z), . . . , ln(z)), where lj(z) : Bn → R+ is a continuous function such that

(∀z∈Bn) : lj(z)> β/(1− |z|), j∈ {1, . . . , n}, (2.1)

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whereβ >√

nis a some constant. For a polydisc A.I. Bandura, N.V. Petrechko and O.B. Skaskiv [6, 7] imposed the restriction (∀z ∈ Dn(0,1)) : lj(z) > β/(1− |zj|), j∈ {1, . . . , n}.A similar condition is used in one-dimensional case by S.N. Strochyk, M.M. Sheremeta, V.O. Kushnir [22, 14, 21].

Note that if R ∈Rn+, |R| ≤ β, z0 ∈Bn and z ∈ Dn[z0, R/L(z0)] then z ∈ Bn (see Remark 1 in [8]).

An analytic function F: Bn → C is said to be of bounded L-index (in joint variables),if there exists n0∈Z+such that for allz∈Bn and for allJ ∈Zn+

|F(J)(z)|

J!LJ(z) ≤max

|F(K)(z)|

K!LK(z) : K∈Zn+, kKk ≤n0

. (2.2)

The least such integer n0 is called the L-index in joint variables of the function F and is denoted byN(F,L,Bn) (see [8]). Entire and analytic in polydisc functions of boundedL-index in joint variables are considered in [4, 5, 6, 7, 10, 13, 19, 18, 16, 17].

ByQ(Bn) we denote the class of functionsL, which satisfy (2.1) and the following condition

(∀R∈Rn+,|R| ≤β, j∈ {1, . . . , n}) : 0< λ1,j(R)≤λ2,j(R)<∞, (2.3) where λ1,j(R) = inf

z0∈Bninf

lj(z)/lj(z0) :z∈Dn

z0, R/L(z0) , λ2,j(R) = sup

z0Bn

sup

lj(z)/lj(z0) :z∈Dn

z0, R/L(z0) . Λ1(R) = (λ1,1(R), . . . , λ1,n(R)), Λ2(R) = (λ2,1(R), . . . , λ2,n(R)).

We need the following results.

Theorem 2.1 ([8]). LetL∈Q(Bn). An analytic inBn functionF has boundedL-index in joint variables if and only if for eachR∈Rn+,|R| ≤β,there existn0∈Z+,p0>0 such that for everyz0∈Bn there existsK0∈Zn+,kK0k ≤n0, and

max

|F(K)(z)|

K!LK(z):kKk ≤n0, z∈Dn

z0, R/L(z0)

≤p0

|F(K0)(z0)|

K0!LK0(z0). (2.4) DenoteL(z) = (ee l1(z), . . . ,eln(z)). The notationLLe means that there exist

Θ1= (θ1,j, . . . , θ1,n)∈Rn+, Θ2= (θ2,j, . . . , θ2,n)∈Rn+

such that∀z∈Bn θ1,jelj(z)≤lj(z)≤θ2,jelj(z) for eachj∈ {1, . . . , n}.

Theorem 2.2 ([8]). LetL∈Q(Bn),LL, β|Θe 1|>√

n.An analytic inBn functionF has bounded L-index in joint variables if and only ife F has boundedL-index in joint variables.

3. Local behaviour of maximum modulus of analytic in ball function

For an analytic inBn functionF we put

M(r, z0, F) = max{|F(z)|:z∈Tn(z0, r)},

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where z0 ∈ Bn, r ∈Rn+. Then M(R, z0, F) = max{|F(z)|: z ∈ Dn[z0, R]}, because the maximum modulus for an analytic function in a closed polydisc is attained on its skeleton.

The following proposition uses an idea about the possibility of replacing universal quantifier by existential quantifier in sufficient conditions of index boundedness [2]. To prove an analog of Hayman’s Theorem we need this theorem which has an independent interest.

Theorem 3.1. Let L ∈ Qn, F : Bn → C be analytic function. If there exist R0, R00∈Rn+, R0< R00,|R00|< β andp1=p1(R0, R00)≥1such that for every z0∈Cn

M R00

L(z0), z0, F

≤p1M R0

L(z0), z0, F

(3.1) thenF is of boundedL-index in joint variables.

Proof. At first, we assume that0< R0 <1< R00.

Letz0∈Bn be an arbitrary point. We expand a functionF in power series F(z) = X

K≥0

bK(z−z0)K = X

k1,...,kn≥0

bk1,...,kn(z1−z01)k1. . .(zn−zn0)kn, (3.2)

wherebK=bk1,...,kn= F(K)K!(z0).

Let µ(R, z0, F) = max{|bK|RK: K ≥ 0} be a maximal term of power series (3.2) and

ν(R) =ν(R, z0, F) = (ν10(R), . . . , νn0(R)) be a set of indices such that

µ(R, z0, F) =|bν(R)|Rν(R),

kν(R)k=

n

X

j=1

νj(R) = max{kKk:K≥0, |bK|RK =µ(R, z0, F)}.

In view of inequality (3.8) we obtain for any|R|<1− |z0|, µ(R, z0, F)≤M(R, z0, F).

Then for givenR0 andR00 with 0<|R0|<1<|R00|< β we conclude M(R0R, z0, F)≤X

k≥0

|bk|(R0R)k ≤X

k≥0

µ(R, z0, F)(R0)k

=µ(R, z0, F)X

k≥0

(R0)k =

n

Y

j=1

1

1−r0jµ(R, z0, F).

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Besides,

lnµ(R, z0, F) = ln{|bν(R)|Rν(R)}= ln

|bν(R)|(RR00)ν(R) 1 (R00)ν(R)

= ln{|bν(R)|(RR00)ν(R)}+ ln 1

(R00)ν(R)

≤lnµ(R00R, z0, F)− kν(R)kln min

1≤j≤nrj00. This implies that

kν(R)k ≤ 1

ln min1≤j≤nrj00(lnµ(R00R, z0, F)−lnµ(R, z0, F))

≤ 1

ln min1≤j≤nr00j

lnM(R00R, z0, F)−ln(

n

Y

j=1

(1−r0j)M(R0R, z0, F))

≤ 1

ln min1≤j≤nr00j lnM(R00R, z0, F)−lnM(R0R, z0, F)

− Pn

j=1ln(1−rj0) min1≤j≤nrj00

= 1

min1≤j≤nr00j lnM(R00R, z0, F) M(R0R, z0, F) −

Pn

j=1ln(1−rj)

min1≤j≤nr00j . (3.3) PutR= L(z10).Now letN(F, z0,L) be theL-index of the functionFin joint variables at point z0 i. e. it is the least integer for which inequality (2.2) holds at point z0. Clearly that

N(F, z0,L)≤ν 1

L(z0), z0, F

=ν(R, z0, F). (3.4)

But

M R00/L(z0), z0, F

≤p1(R0, R00)M R0/L(z0), z0, F

. (3.5)

Therefore, from (3.3), (3.4), (3.5) we obtain that∀z0∈Bn N(F, z0,L)≤−P2

j=1ln(1−r0j)

ln min{r001, r200} + lnp1(R0, R00) ln min{r001, r200}.

This means that F has bounded L-index in joint variables, if 0 < R0 < 1 < R00,

|R00|< β.

Now we will prove the theorem for any 0 < R0 < R00, |R00| < β. From (3.1) with 0< R1< R2 it follows that

max

|F(z)|:z∈Tn

z0, 2R00 R0+R00

R0+R00 2L(z0)

≤P1max

|F(z)|:z∈Tn

z0, 2R0 R0+R00

R0+R00 2L(z0)

.

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DenotingL(z) =e R2L(z)0+R00,we obtain max

(

|F(z)|:z∈Tn z0, 2R00 (R0+R00)eL(z0)

!)

≤P1max (

|F(z)|:z∈Tn z0, 2R00 (R0+R00)eL(z0)

!) ,

where 0< R02R+R000 <1< R2R0+R0000.Taking into account the first part of the proof, we conclude that the function F has bounded L-index in joint variables. By Theoreme 2.2, the functionF is of boundedL-index in joint variables.

Also the corresponding necessary conditions are valid.

Theorem 3.2. LetL∈Q(Bn).If an analytic in Bn functionF has boundedL-index in joint variables then for anyR0, R00∈Rn+, R0< R00,|R00| ≤β,there exists a number p1=p1(R0, R00)≥1 such that for everyz0∈Bn inequality (3.1)holds.

Proof. LetN(F,L) =N <+∞.Suppose that inequality (3.1) does not hold i.e. there existR0, R00,0<|R0|<|R00|< β,such that for eachp≥1 and for somez0=z0(p)

M R00

L(z0), z0, F

> pM R0

L(z0), z0, F

. (3.6)

By Theorem 2.1, there exists a number p0=p0(R00)≥1 such that for everyz0∈Bn and some K0 ∈Zn+,kK0k ≤N, (i.e.n0 =N, see proof of necessity of Theorem 2.1 in [8]) one has

M R00

L(z0), z0, F(K0)

≤p0|F(K0)(z0)|. (3.7) We put

b1=p0

n

Y

j=2

λN2,j(R00)

(N!)n−1

N

X

j=1

(N−j)!

(r100)j

r100r200. . . rn00 r01r20. . . r0n

N ,

b2=p0

n Y

j=3

λN2,j(R00)

(N!)n−2 N

X

j=1

(N−j)!

(r002)j

r002. . . rn00 r02. . . r0n

N 1, 1

(r10)N

, . . .

bn−1=p0λN2,n(R0)N!

N

X

j=1

(N−j)!

(r00n−1)j

rn−100 r00n rn−10 r0n

N

max

1, 1

(r10. . . rn−20 )N

,

bn=p0

N

X

j=1

(N−j)!

(rn00)j

 rn00

rn0 N

max

1, 1

(r01. . . r0n−1)N

and

p= (N!)np0

r100r002. . . rn00 r01r02. . . r0n

N

+

n

X

k=1

bk+ 1.

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Letz0=z0(p) be a point for which inequality (3.6) holds andK0be such that (3.7) holds and

M R0

L(z0), z0, F

=|F(z)|, M r00

L(z0), z0, F(J)

=|F(J)(zJ)|

for everyJ ∈Zn+,kJk ≤N.We apply Cauchy’s inequality

|F(J)(z0)| ≤J!

L(z0) R0

J

|F(z)| (3.8)

for estimate the difference

|F(J)(zJ,1 , zJ,2 , . . . , zJ,n )−F(J)(z10, zJ,2 , . . . , zJ,n )|

=

Z zJ,1 z01

kJk+1F

∂z1j1+1∂z2j2. . . ∂znjn

(ξ, zJ,2 , . . . , zJ,n )dξ

kJk+1F

∂zj11+1∂zj22. . . ∂znjn

(z(j

1+1,j2,...,jn))

r100

l1(z0). (3.9) Taking into account (z10, zJ,2 , . . . , zJ,n)∈Dn[z0,L(zR000)],for allk∈ {1, . . . , n},

|zJ,k−zk0|= rk00

lk(z0), lk(z10, zJ,2 , . . . , zJ,n)≤λ2,k(R00)lk(z0) and (3.8) withJ =K0,by Theorem 2.1 we have

|F(J)(z01, zJ,2, . . . , zJ,n )|

≤J!lj11(z10, zJ,2 , . . . , zJ,n )Qn

k=2ljkk(z10, zJ,2 , . . . , zJ,n)

K0!LK0(z0) p0|F(K0)(z0)|

≤ J!LJ(z0)Qn

k=2λj2,kk (R00) K0!LK0(z0) p0K0!

L(z0) R0

K0

|F(z)|

= p0J!LJ(z0)Qn

k=2λj2,kk (R00)

(R0)K0 |F(z)|. (3.10)

From inequalities (3.9) and (3.10) it follows that

kJk+1F

∂z1j1+1∂z2j2. . . ∂zjnn

(z(j

1+1,j2,...,jn))

≥ l1(z0) r100

n|F(J)(zj)| − |F(J)(z10, zJ,2 , . . . , zJ,n )|o

≥ l1(z10)

r100 |F(J)(zj)| −p0J!L(j1+1,j2,...,jn)(z0)Qn

k=2λj2,kk (R00)

r001(R0)K0 |F(z)|.

Then

|F(K0)(zK0)| ≥l1(z0) r100

kK0k−1f

∂z1k10−1∂z2k02. . . ∂znk0n

(z(k0

1−1,k02,...,k0n))

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−p0(k10−1)!k20!. . . k0n!LK0(z0)Qn i=2λk

0 i

2,i(R00) r100(R0)K0 |F(z)|

≥ l12(z0) (r001)2

kK0k−2f

∂z1k01−2∂z2k02. . . ∂znk0n

(z(k0

1−2,k02,...,k0n))

−p0(k10−2)!k20!. . . k0n!LK0(z0)Qn

i=2λk2,i0i(R00) (r001)2(R0)K0 |F(z)|

−p0(k01−1)!k20!. . . k0n!LK0(z0)Qn i=2λk

0 i

2,i(r00i) r100(R0)K0 |F(z)|

. . .

≥ l1k01(z0) (r001)k01

kK0k−k01f

∂zk202. . . ∂zkn0n

(z(0,k 0 2,...,k0n))

− p0

(R0)K0LK0(z0)

n

Y

i=2

λk2,i0i(R00)

!

k20!. . . k0n!

k01

X

j1=1

(k10−j1)!

(r100)j1 |F(z)|. . .

≥lk

0 1

1 (z0) (r100)k10

lk

0 2

2 (z0) (r002)k02

kK0k−k01−k02f

∂zk303. . . ∂zkn0n

(z(0,0,k 0 3,...,kn0))

−lk101(z0)p0L(0,k20,...,k0n)(z0) (r001)k01(R0)K0

n

Y

i=3

λk

0 i

2,i(R00)

!

k30!. . . k0n!

k02

X

i2=1

(k02−j2)!

(r200)j2 |F(z)|

− p0

(R0)K0LK0(z0)

n

Y

i=2

λk2,i0i(R00)

!

k20!. . . k0n!

k01

X

j1=1

(k10−j1)!

(r100)j1 |F(z)|

. . .

L(z0) R00

|F(z0)| − |F(z)|

b

X

i=1

˜bi, (3.11)

where in view of the inequalitiesλ2,i(R00)≥1 andR00≥R0 we have

˜b1= p0

(R0)K0LK0(z0)

n

Y

i=2

λk

0 i

2,i(R00)

!

k02!. . . kn0!

k10

X

j1=1

(k01−j1)!

(r001)j1

=

L(z0) R00

K0R00 R0

K0 p0

n

Y

i=2

λk2,i0i(R00)

!

k02!. . . kn0!

k01

X

j1=1

(k01−j1)!

(r001)j1

L(z0) R00

K0 b1,

˜b2= p0

(R0)K0LK0(z0) n

Y

i=3

λk2,ii0(R00)

k03!. . . kn0! (r001)k01

k02

X

j2=1

(k20−j2)!

(r200)j2 ≤ L(z0)

R00 K0

b2, . . .

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˜bn−1= p0

(R0)K0LK0(z0k2,nn0 (R00) k0n!

(r001)k01. . .(r00n−2)kn−20 ×

×

k0n−1

X

jn−1=1

(kn−10 −jn−1)!

(r00n−1)jn−1

L(z0) R00

K0 bn−1,

˜bn= p0

(R0)K0LK0(z0) 1

(r100)k10. . .(rn−100 )k0n−1

k0n

X

jn=1

(k0n−jn)!

(r00n)jn

L(z0) R00

K0 bn. Thus, (3.11) implies that

|F(K0)(zK0)| ≥

L(z0) R00

K0

|F(z)|

|F(z0)|

|F(z)|−

n

X

j=1

bj

 . But in view of (3.6) and a choice ofp we have

|F(z0)|

|F(z)| ≥p>

n

X

j=1

bj. Thus, (3.7) and (3.8) imply

|F(K0)(zK0)| ≥

L(z0) R00

K0

|F(z)|

 p

n

X

j=1

bj

L(z0) R00

K0

 p

n

X

j=1

bj

|F(K0)(z0)|(R0)K0 K0!LK0(z0)

r01. . . r0n r100. . . rn00

N

 p

n

X

j=1

bj

|F(K0)(zK0)|

p0(n!)n . Hence, we havep≤p0

r01...r0n r001...r00n

N

(N!)n+Pn

j=1bj,but this contradicts the choice of

p.

4. Analogue of Theorem of Hayman for analytic in a ball function of bounded L-index in joint variables

Theorem 4.1. Let L∈Q(Bn). An analytic functionF in Bn has bounded L-index in joint variables if and only if there existp∈Z+ andc∈R+ such that for eachz∈Bn

max

|F(J)(z)|

LJ(z) : kJk=p+ 1

≤c·max

|F(K)(z)|

LK(z) : kKk ≤p

. (4.1)

Proof. LetN=N(F,L,Bn)<+∞.The definition of the boundedness ofL-index in joint variables yields the necessity withp=N andc= ((N+ 1)!)n.

We prove the sufficiency. ForF ≡0 theorem is obvious. Thus, we suppose that F 6≡0.Denote β= (βn, . . . ,βn).

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Assume that (4.1) holds,z0∈Bn, z∈Dn[z0,L(zβ0)].For allJ ∈Zn+,kJk ≤p+ 1, one has

|F(J)(z)|

LJ(z0) ≤ΛJ2(β)|F(J)(z)|

LJ(z) ≤c·ΛJ2(β) max

|F(K)(z)|

LK(z) : kKk ≤p

≤c·ΛJ2(β) max

Λ−K1 (2)|F(K)(z)|

LK(z0) :kKk ≤p

≤BG(z), (4.2)

whereB=c·max{ΛK2 (β) : kKk=p+ 1}max{Λ−K1 (β) : kKk ≤p},and G(z) = max

|F(K)(z)|

LK(z0) : kKk ≤p

. We choose

z(1)= (z1(1), . . . , zn(1))∈Tn(z0, 1 2β√

nL(z0)) and

z(2)= (z1(2), . . . , zn(2))∈Tn(z0, β L(z0)) such thatF(z(1))6= 0 and

|F(z(2))|=M β

L(z0), z0, F

6= 0. (4.3)

These points exist, otherwise ifF(z)≡0 on skeleton Tn

z0, 1 2β√

nL(z0)

or Tn

z0, β L(z0)

then by the uniqueness theorem F ≡0 in Bn. We connect the points z(1) and z(2) with plane

α=





z2=k2z1+c2, z3=k3z1+c3, . . . zn=knz1+cn, where

ki= zi(2)−zi(1) z1(2)−z1(1)

, ci =zi(1)z(2)1 −z(2)i z1(1) z(2)1 −z(1)1

, i= 2, . . . , n.

It is easy to check thatz(1) ∈αandz(2)∈α.LetG(ze 1) =G(z)|α be a restriction of the functionGontoα.

For every K ∈ Zn+ the function F(K)(z)

α is analytic function of variable z1

and ˜G(z(1)1 ) = G(z(1))

α 6= 0 becauseF(z(1))6= 0. Hence, all zeros of the function F(K)(z)

αare isolated as zeros of a function of one variable. Thus, zeros of the function G(z˜ 1) are isolated too. Therefore, we can choose piecewise analytic curveγontoαas following

z=z(t) = (z1(t), k2z1(t) +c2, . . . , knz1(t) +cn), t∈[0,1],

(11)

which connect the pointsz(1), z(2) and such thatG(z(t))6= 0 and Z 1

0

|z10(t)|dt≤ 2β

√nl1(z01).

For a construction of the curve we connectz1(1) andz1(2) by a line z1(t) = (z1(2)−z1(1))t+z1(1), t∈[0,1].

The curveγcan cross pointsz1at which the functionG(ze 1) = 0.The number of such pointsm=m(z(1), z(2)) is finite. Let (z1,k ) be a sequence of these points in ascending order of the value |z(1)1 −z1,k|, k∈ {1,2, ..., m}. We choose

r < min

1≤k≤m−1{|z1,k −z1,k+1 |,|z1,1 −z(1)1 |,|z1,m −z1(2)|, 2β2−1 2π√

nβl1(z0)}.

Now we construct circles with centers at the points z1,k and corresponding radii r0k< 2rk such thatG(ze 1)6= 0 for allz1 on the circles. It is possible, becauseF 6≡0.

Every such circle is divided onto two semicircles by the linez1(t). The required piecewise-analytic curve consists with arcs of the constructed semicircles and segments of linez1(t), which connect the arcs in series between themselves or with the points z1(1), z1(2). The length ofz1(t) in C(but notz(t) inCn!) is lesser than

β/√ n

l1(z0) + 1 2√

nβl1(z0)+πr≤ 2β

√nl1(z0). Then

Z 1 0

|zs0(t)|dt=|ks| Z 1

0

|z10(t)|dt≤ |zs(2)−zs(1)|

|z1(2)−z1(1)|

√ 2β nl1(z0)

≤ 2β2+ 1 2√

nβls(z0) 2√

nβl1(z0) 2β2−1

√ 2β

nl1(z0) ≤ 2β(2β2+ 1) (2β2−1)√

nls(z0), s∈ {2, . . . , n}.

Hence,

Z 1 0

n

X

s=1

ls(z0)|zs0(t)|dt≤ 2β(2β2+ 1)√ n

2−1 =S. (4.4)

Since the functionz=z(t) is piece-wise analytic on [0,1], then for arbitraryK∈Zn+, J ∈Zn+,kKk ≤p,either

|F(K)(z(t))|

LK(z0) ≡ |F(J)(z(t))|

LJ(z0) , (4.5)

or the equality

|F(K)(z(t))|

LK(z0) = |F(J)(z(t))|

LJ(z0) (4.6)

holds only for a finite set of pointstk ∈[0; 1].

Then for function G(z(t)) as maximum of such expressions |F(J)LJ(z(z(t))|0) by all kJk ≤ptwo cases are possible:

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1. In some interval of analyticity of the curve γ the function G(z(t)) identically equals simultaneously to some derivatives, that is (4.5) holds. It means that G(z(t)) ≡ |F(J)LJ(z(z(t))|0) for some J, kJk ≤ p. Clearly, the function F(J)(z(t)) is analytic. Then |F(J)(z(t))| is continuously differentiable function on the in- terval of analyticity except points where this partial derivative equals zero

|F(j1,j2)(z1(t), z2(t))| = 0. However, there are not the points, because in the opposite caseG(z(t)) = 0.But it contradicts the construction of the curveγ.

2. In some interval of analyticity of the curve γ the function G(z(t)) equals si- multaneously to some derivatives at a finite number of points tk, that is (4.6) holds. Then the pointstk divide interval of analyticity onto a finite number of segments, in which of them G(z(t)) equals to one from the partial derivatives, i. e. G(z(t)) ≡ |FL(J)J(z(t))|(z0) for some J, kJk ≤ p. As above, in each from these segments the functions|F(J)(z(t))|, andG(z(t)) are continuously differentiable except the pointstk.

The inequality

d

dt|f(t)| ≤

df(t) dt

holds for complex-valued functions of real argument outside a countable set of points.

In view of this fact and (4.2) we have d

dtG(z(t))≤maxn 1 LJ(z0)

d

dtF(J)(z(t))

: kJk ≤po

≤maxnXn

s=1

kJk+1F

∂z1j1. . . ∂zsjs+1. . . ∂zjnn

(z(t))

|zs0(t)|

Lj(z0) : kJk ≤po

≤maxnXn

s=1

kJk+1F

∂zj11. . . ∂zsjs+1. . . ∂znjn

(z(t))

ls(z0)|zs0(t)|

l1j1(z0). . . ljs1+1(z0). . . ljnn(z0) : kJk ≤po

≤Xn

s=1

ls(z0)|zs0(t)|

maxn|F(j)(z(t))|

LJ(z0) : kJk ≤p+ 1o

≤Xn

s=1

ls(z0)|z0s(t)|

BG(z(t)).

Therefore, (4.4) yields

lnG(z(2)) G(z(1)) =

Z 1 0

1 G(z(t))

d

dtG(z(t))dt ≤B

Z 1 0

n

X

s=1

ls(z0)|zs0(t)|dt≤S·B.

Using (4.3), we deduce M

β

L(z0), z0, F

≤G(z(2))≤G(z(1))eSB.

(13)

Sincez(1)∈Tn(z0,nL(z1 0)),the Cauchy inequality holds

|F(J)(z(1))|

LJ(z0) ≤J!(2β√ n)kJkM

1 2β√

nL(z0), z0, F

. for allJ ∈Zn+.Therefore, forkJk ≤pwe obtain

G(z(1))≤(p!)n(2β√ n)pM

1 2β√

nL(z0), z0, F

,

M β

L(z0), z0, F

≤eSB(p!)n(2β√ n)pM

1 2β√

nL(z0), z0, F

.

Hence, by Theorem 3.1 the functionF has boundedL-index in joint variables.

The following result was also obtained for other classes of holomorphic functions in [21, 11, 7].

Theorem 4.2. Let L∈Q(Bn). An analytic functionF in Bn has bounded L-index in joint variables if and only if there exist c ∈ (0; +∞) and N ∈ N such that for each z∈Bn the inequality

N

X

kKk=0

|F(K)(z)|

K!LK(z) ≥c

X

kKk=N+1

|F(K)(z)|

K!LK(z). (4.7)

Proof. Let 1β < θj < 1, j ∈ {1, . . . , n}, Θ = (θ1, . . . , θn). If the function F has bounded L-index in joint variables then by Theorem 2.2 F has bounded L-indexe in joint variables, where Le = (el1(z), . . . ,eln(z)),elj(z) = θjlj(z), j ∈ {1, . . . , n}. Let Ne =N(F,L,e Bn). Therefore,

max

|F(K)(z)|

K!LK(z): kKk ≤Ne

= max

K|F(K)(z)|

K!eLK(z) :kKk ≤Ne )

n

Y

s=1

θNsemax

|F(K)(z)|

K!eLK(z):kKk ≤Ne

n

Y

s=1

θNse|F(J)(z)|

J!eLJ(z) =

n

Y

s=1

θNse−js|F(J)(z)|

J!LJ(z) for allJ ≥0and

X

kJk=N+1e

|F(J)(z)|

J!Lj(z) ≤max

|F(K)(z)|

K!LK(z):kKk ≤Ne

X

kJk=Ne+1

θsjsNe

=

n

Y

i=1

θs

1−θs

max

|F(K)(z)|

K!LK(z):kKk ≤Ne

n

Y

i=1

θs

1−θs Ne

X

kKk=0

|F(K)(z)|

K!LK(z). Hence, we obtain (4.7) withN =Ne and

c=

n

Y

i=1

θs

1−θs.

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