Rev. Anal. Num´er. Th´eor. Approx., vol. 35 (2006) no. 2, pp. 141–146 ictp.acad.ro/jnaat
DOUBLE INEQUALITIES OF NEWTON’S QUADRATURE RULE
MARIUS HELJIU∗
Abstract. In this paper double inequalities of Newton’s quadrature rule are given.
MSC 2000. 65D32.
Keywords. Newton’s inequality, double integral inequalities, numerical inte- gration.
1. INTRODUCTION
In the papers [1], [2], [3], [4], [5], [7] and [8] relatively double inequalities of quadratures rules of the trapezoid and Simpson were given. In this note we will obtain upper and lower error bounds for Newton’s quadrature rule.
Letf : [a, b]→R, f ∈C4([a, b]) andx1, x2 ∈[a, b] so thatx1 = 2a+b3 , x2 =
a+2b
3 , then as it is well known [6] the relation is obtained (1.1)
Z b a
f(x)dx= b−a8 [f(a) + 3f(x1) + 3f(x2) +f(b)] +R, where
(1.2) R=
Z b a
ϕ(x)f(4)(x)dx.
The function ϕis given by the relation (h denotes b−a3 ):
(1.3) ϕ(x) =
(x−a)4
4! −3h8 (x−a)3! 3, x∈[a, x1]
(x−a)4
4! −3h8 (x−a)3! 3 − 9h8 (x−x3!1)3, x∈[x1, x2]
(x−a)4
4! −3h8 (x−a)3! 3 − 9h8 (x−x3!1)3 −9h8 (x−x3!2)3, x∈[x2, b].
2. MAIN RESULT
Under the assumptions of the quadrature formula (1.1) we have the next theorem:
∗University of Petro¸sani, Department of Mathematics and Computer Science, Romania, e-mail: [email protected].
Theorem 2.1. Let f ∈C4(a, b).Then:
23γ4−15S3
51840 (b−a)5 ≤ b−a8 [f(a) + 3f(x1) + 3f(x2) +f(b)]− Z b
a
f(x)dx
≤ 23Γ518404−15S3(b−a)5, (2.1)
whereγ4, Γ4 ∈R, γ4 ≤f(4)(x)≤Γ4,for anyx∈[a, b]andS3 = f(3)(b)−fb−a(3)(a). If γ4= min
x∈[a,b]f(4)(x), Γ4 = max
x∈[a,b]f(4)(x) then inequalities are sharp.
Proof. From (1.2) integrating by parts we get : (2.2)
Z b a
ϕ(x)f(4)(x)dx= Z b
a
f(x)dx−b−a8 [f(a) + 3f(x1) + 3f(x2) +f(b)]. It is easy to see [6] that we get the equality:
(2.3)
Z b a
ϕ(x)dx=−(b−a)64805. From (2.2) and (2.3) we get the equalities:
Z b a
hf(4)(x)−γ4
iϕ(x)dx=
= Z b
a
f(x)dx− b−a8 [f(a) + 3f(x1) + 3f(x2) +f(b)] + 6480γ4 (b−a)5 (2.4)
and Z b
a
hΓ4−f(4)(x)iϕ(x)dx=
=− Z b
a
f(x)dx+b−a8 [f(a) + 3f(x1) + 3f(x2) +f(b)]− 6480Γ4 (b−a)5. (2.5)
On the other hand:
(2.6)
Z b a
hf(4)(x)−γ4iϕ(x)dx≤ max
x∈[a,b]|ϕ(x)|
Z b a
f(4)(x)−γ4dx.
From (1.3) we get:
(2.7) max
x∈[a,b]|ϕ(x)|= (b−a)34564. On the other hand the equality follows:
Z b a
f(4)(x)−γ4
dx=
Z b a
(f(4)(x)−γ4)dx
=f(3)(b)−f(3)(a)−γ4(b−a) = (S3−γ4)(b−a).
(2.8)
From the relations (2.4), (2.6), (2.7) and (2.8) it follows : Z b
a
f(x)dx−b−a8 [f(a) + 3f(x1) + 3f(x2) +f(b)]≤
≤ 15S518403−23γ4(b−a)5, (2.9)
the first inequality of (2.1).
We also have:
(2.10)
Z b a
h
Γ4−f(4)(x)iϕ(x)dx≤ max
x∈[a,b]|ϕ(x)|
Z b a
Γ4−f(4)(x)dx and
(2.11)
Z b a
Γ4−f(4)(x)dx= Z b
a
(Γ4−f(4)(x))dx=
= Γ4(b−a)+f(3)(a)−f(3)(b) = (Γ4−S3)(b−a).
By analogy from (2.5), (2.7), (2.10) and (2.11) we get:
Z b a
f(x)dx−b−a8 [f(a) + 3f(x1) + 3f(x2) +f(b)]≥
≥ 15S518403−23Γ4(b−a)5. (2.12)
The last relation and (2.9) lead us to the inequality (2.1).
To show that inequality (2.1) is sharp we consider the function f given by the relation f(x) = (x−a)4.It is easy to see that the equalities f(4)(x) = 24 and γ4 = Γ4= 24, S3 = 24 are obtained.
Calculating the three members of the inequality (2.1) under the given cir- cumstances, we notice that these have the common value given by the expres- sion 2701 (b−a)5.Hence, we deduce that the inequality (2.1) is sharp.
Another relation is given by the next theorem:
Theorem 2.2. Under the assumptions of Theorem 2.1we have:
7γ4−15S3
51840 (b−a)5 ≤ Z b
a
f(x)dx−b−a8 [f(a) + 3f(x1) + 3f(x2) +f(b)]
≤ 7Γ518404−15S3(b−a)5. (2.13)
If γ4 = min
x∈[a,b]f(4)(x),Γ4 = max
x∈[a,b]f(4)(x) then the inequalities (2.13) are sharp.
Proof. From (2.4), (2.6), (2.7)and (2.8) we have:
− Z b
a
f(x)dx+b−a8 [f(a) + 3f(x1) + 3f(x2) +f(b)]≤
≤ 15S518403−7γ4(b−a)5. (2.14)
By analogy from (2.5), (2.10), (2.11) and (2.12) we have:
Z b a
f(x)dx−b−a8 [f(a) + 3f(x1) + 3f(x2) +f(b)]≤
≤ 7Γ518404−15S3(b−a)5. (2.15)
From (2.14) and (2.15) we will have immediately the inequalities (2.13).
To show that the inequalities are sharp we choose f(x) = (x−a)4 and we
follow the steps of the proof for Theorem 2.1.
The next theorem offers us inequalities which do not depend uponS3. Theorem 2.3. Under the assumptions of Theorem 2.1we have:
7γ4−23Γ4
103680 (b−a)5 ≤ Z b
a
f(x)dx−b−a8 [f(a) + 3f(x1) + 3f(x2) +f(b)]≤
≤ 7Γ1036804−23γ4(b−a)5. (2.16)
If γ4 = min
x∈[a,b]f(4)(x), Γ4 = max
x∈[a,b]f(4)(x) then the inequalities (2.16) are sharp.
Proof. The inequalities (2.16) are easily deduced by (2.9) and (2.14) , re- spectively (2.12) and (2.15). To show that the inequalities are sharp we follow
the steps of the proof for Theorem 2.1.
In use the next theorem is important:
Theorem 2.4. Under the assumptions of Theorem 2.1we have:
23γ4−15S3
51840n4 (b−a)5≤
≤ b−a8n
"
f(a) +f(b) + 2
n−1
X
i=1
f(xi) + 3
n
X
i=1
f(x0i) + 3
n
X
i=1
f(x00i)
#
− Z b
a
f(x)dx
≤ 23Γ51840n4−15S43(b−a)5, (2.17)
where xi = a+ih, h = b−an , i = 0,1, ..., n and x0i, x00i divide every interval [xi, xi+1]in three equal parts.
Proof. We divide each interval [xi, xi+1] in the equal parts by points x0i, x00i, then we use Theorem 2.1 on the interval [xi, xi+1] :
23γ4−15S3i
51840 (xi+1−xi)5 ≤
≤ xi+18−xif(xi) + 3f(x0i) + 3f(x00i) +f(xi+1)− Z xi+1
xi
f(x)dx
≤ 23Γ518404−15S3i(xi+1−xi)5, (2.18)
whereS3i = f(3)(xi+1)−fh (3)(xi), i= 0,1, ..., n−1.By adding the formula we have got so far for i= 0,1, ..., n−1 and by noticing that
n−1
X
i=0
S3i = f(3)(b)−fh (3)(a) we
get the relation we wanted.
From Theorem 2.2, following the steps done, we get:
Theorem 2.5. Under the assumptions of Theorem 2.1we have:
7γ4−15S3
51840n4 (b−a)5 ≤
≤ Z b
a
f(x)dx−b−a8n
"
f(a) +f(b) + 2
n−1
X
i=1
f(xi) + 3
n
X
i=1
f(x0i) + 3
n
X
i=1
f(x00i)
#
≤ 7Γ51840n4−15S43(b−a)5. (2.19)
Proof. Proving this theorem is similarly to proving Theorem 2.4. Then we
use Theorem 2.2.
Also Theorem 2.3 leads us to:
Theorem 2.6. Under the assumptions of Theorem 2.1we have:
7γ4−23Γ4
103680n4(b−a)5≤
≤ Z b
a
f(x)dx−b−a8n
"
f(a) +f(b) + 2
n−1
X
i=1
f(xi) + 3
n
X
i=1
f(x0i) + 3
n
X
i=1
f(x00i)
#
≤ 7Γ103680n4−23γ44(b−a)5. (2.20)
Proof. Proving this theorem is similarly to proving Theorem 2.4. Then we
use Theorem 2.3.
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Received by the editors: January 12, 2006.