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Rev. Anal. Num´er. Th´eor. Approx., vol. 34 (2005) no. 1, pp. 115–121 ictp.acad.ro/jnaat

AN APPROXIMATION OPERATOR OF STANCU TYPE

SILVIA TOADER

Abstract. We study the behavior of Stancu-Goldman’s operator on the second degree functions.

MSC 2000. 41A10, 60E05.

Keywords. Stancu’s approximation operator, Friedman’s distribution.

1. INTRODUCTION

Using the P`olya-Eggenberger-Markov distribution, D. D. Stancu has defined in [4] a polynomial approximation operator, which today is bearing his name (see [1]). The above distribution was generalized by B. Friedman in [2]. Using this new distribution, R. N. Goldman has defined in [3] an approximation operator of Stancu type for which has proved that it preserves the first degree functions. In this paper, we begin the study of the behavior of this operator on the second degree functions. This is necessary for the application of Popoviciu- Bohman-Korovkin approximation theorem (see [1]).

2. FRIEDMAN’S DISTRIBUTION

In [2] it is considered the following probabilistic model: an urn contains N balls,aof which are white andbblack. A ball is draw out at random, its color noted and it is returned together with c balls of the same color and dballs of the opposite color. This procedure is repeated n times. We denote with P(n, k) the probability that the total number of white balls chosen be k.

This model was studied in detail in [3] where the following recurrence rela- tion

P(n, k) =P(n−1, k−1)·a+(k−1)·c+(n−k)·d

N+(n−1)·(c+d) +P(n−1, k)·b+(n−k−1)·c+k·d N+(n−1)·(c+d)

is established. If we denote

a

N =x, Nc =α, Nd =β

Department of Mathematics, Technical University of Cluj-Napoca, Romania, e-mail:

[email protected].

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and P(n, k) =P(n, k, x) the recurrence relation becomes P(n, k, x) =s(n−1, k−1, x)·P(n−1, k−1, x)

+t(n−1, k, x)·P(n−1, k, x), where

s(n, k, x) = [x+k·α+ (n−k)·β]·ρn

and

t(n, k, x) = 1s(n, k, x) with

ρn= 1+n·(α+β)1 .

For β = 0 we obtain the P`olya-Eggenberger-Markov distribution with the explicit expression

P(n, k, x) = nkx(k,−α)(1−x)1(n,−α)(n−k,−α), where

x(k,−α)=x(x+α)...[x+ (k−1)α].

As we have shown in [5], such an expression seems to be impossible to obtain in the case β6= 0.

3. THE DETERMINATION OF THE MOMENTS

Though the expressions of the distribution are missing, as it is shown in [3]

we can calculate its moments of order r Mr(n, x) =

n

X

k=0

kr·P(n, k, x).

Of course

M0(n, x) = 1, Mr(1, x) =x.

For the calculation of other moments, the following recurrence relation Mr(n+ 1, x) =

r

X

i=0

Mi(n, x)·Γ(r, n, x, i) is used, where

Γ(r, n, x, i) = Φ(r, n, i)·x+ Ψ(r, n, i) with

Φ(r, n, r) = 0, Ψ(r, n, r) = 1 +r·(α−β)·ρn

and

Φ(r, n, i) = ri·ρn, Ψ(r, n, i) =h i−1r ·(α−β) +β·n· rii·ρn, i < r.

In the special case r = 1 we obtain:

M1(n+ 1, x) = [1 + (α−β)·ρnM1(n, x) + (x+β·n)·ρn which leads at

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Lemma 1. There exist the constants pn>0, qn≥0, such that (1) M1(n, x) =pn·x+qn, n≥1.

The proof is done by mathematical induction, starting with the initial values p1 = 1, q1 = 0

obtaining the recurrence relations

pn+1 =µn·pn+ρn>0 and

qn+1 =µn·qn+β·n·ρn≥0, where

µn= [1 +αβ+ (α+β)·n]·ρn. To get explicit expressions we use the following

Lemma 2. If the sequence (xn)n≥l verifies the recurrence relation xn+1=An·xn+Bn, nl

then it has the expression xn=

n−1

X

i=l

Bi

n−1

Y

j=i+1

Aj

+xl

n−1

Y

i=l

Ai, n > l with the convention

n−1

Y

j=n

· · ·= 1.

We obtain

Theorem 1. The coefficients of the mean values(1) have the expressions pn=

n−1

X

i=0

ρi

n−1

Y

j=i+1

µj

and

qn=β·

n−1

X

i=0

i·ρi

n−1

Y

j=i+1

µj

. Analogously, for the moments of order two we have

Theorem 2. There exist the positive constants un, vn, wn such that M2(1, x) =x

and

(2) M2(n, x) =un·x2+vn·x+wn, n≥2,

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where

un=

n−1

X

i=1

ρi·pi·

n−1

Y

j=i+1

ϕj

,

vn=

n−1

X

i=1

(2·ρi·qi+ψi·pi+ρi

n−1

Y

j=i+1

ϕj

+

n−1

Y

i=1

ϕi,

wn=

n−1

X

i=1

i·qi+β·i·ρi

n−1

Y

j=i+1

ϕj

, with

ϕi = [1 + 2·(α−β) + (α+β)·i]·ρi

and

ψi = (α−β+ 2·β·i)·ρi. Proof. Forr= 2 the recurrence relation is

M2(n+ 1, x) =ϕn·M2(n, x) + (2·ρn·x+ψnM(n, x) +ρn·(x+β·n).

So

M2(2, x) = 2·ρ1·x2+ (ϕ1+ψ1+ρ1x+β·ρ1,

thus (2) is verified for n = 2. If we assume it to be valid for a given n, we deduce

M2(n+ 1, x) = (un·x2+vn·x+wnϕn

+ (pn·x+qn)·(2·ρn·x+ψn) +ρn·(x+β·n).

We have so (2) for n+ 1,with

un+1 =ϕn·un+ 2·ρn·pn,

vn+1 =ϕn·vn+ 2·ρn·qn+ψn·pn+ρn and

wn+1 =ϕn·wn+ψn·qn+β·n·ρn.

For ending the proof it is sufficient to apply the last lemma with the initial values

u1 = 0, v1 = 1 and w1 = 0.

4. THE DEFINITION OF THE APPROXIMATION OPERATOR

Using Friedman’s distribution, the following operator Un:C[a, b]C[0,1]

was defined in [3] by

(3) (Unf)(x) =

n

X

k=0

P(n, k, x)·f(xn,k),

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where

axn,0< xn,1 < ... < xn,nb.

This operator is linear, positive, of polynomial type, and with the property that

Une0 =e0, where

ek(x) =xk, k = 0,1,2, ...

To apply Korovkin’s approximation theorem (see [1]) the knots xn,kmust be determined so that

Unekek, n→ ∞, k= 1,2.

As it is stated in [3], Ch. Micchelli had the idea of choosing the knots as follows.

Theorem 3. If the interval of definition of the functions verifies the con- dition

[a, b]⊇hpqn

n,n−qp n

n

i, where pn, qn are from(1), then choosing the knots

xn,k = k−qp n

n , k= 0,1, ..., n,

the operator (3)reproduces the linear functions such as it has the property Une1 =e1.

The proof is done by direct computation. In a similar way we obtain Theorem 4. In the conditions of the above theorem, we have

Une2 = p12

n ·hun·e2+ (vn−2·qn·pne1+ (wnqn2e0i. Proof. Step by step we have

(Une2)(x) =

n

X

k=0

k−q

n

pn

2

·P(n, k, x)

= p12

n ·hM2(n, x)−2·qn·M1(n, x) +qn2i

= p12

n ·hun·x2+vn·x+wn−2·qn·(pn·x+qn) +qn2i

which gives the desired result.

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5. A SPECIAL CASE

Choosing β= 0 we obtain Stancu’s operator. Let us study the case α= 0.

We have first of all

ρn= 1+β·n1 andµn= 1+β·(n−1)1+β·n . As

n−1

Y

j=i+1

µj = 1+β·(n−1)1+β·i it follows that

pn= 1+β·(n−1)n andqn= 2·[1+β·(n−1)]β·n·(n−1) . Then

ϕn= 1+β·(n−2)1+β·n andψn= β·(2·n−1)1+β·n . So

n−1

Y

j=i+1

ϕj = [1+β·(i−1)]·(1+β·i) [1+β·(n−2)]·[1+β·(n−1)], which gives

un= [1+β·(n−2)]·[1+β·(n−1)]n·(n−1) , vn= n·[β·n·(n−2)+1]

[1+β·(n−2)]·[1+β·(n−1)]

and

wn= β·n·(n−1)·[β·(3·n2−5·n−2)+6]

12·[1+β·(n−2)]·[1+β·(n−1)] . We deduce that

un

p2n →1, n→ ∞, and

vn−2·pn·qn

p2n →0, n→ ∞, but

wnqn2

p2n → ∞, n→ ∞, soUne2 does not converge.

It remains as an open problem that of determination of the parameters αand β such that

Une2e2, n→ ∞.

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REFERENCES

[1] Altomare, F. andCampiti, M.,Korovkin-type approximation theory and its application, Walter de Gruyter, Berlin-New York, 1994.

[2] Friedman, B.,A simple urn model, Comm. Pure Appl. Math.,2, pp. 59–70, 1949.

[3] Goldman, R. N., Urn models, approximations, and splines, J. Approx. Theory, 54, pp. 1–66, 1988.

[4] Stancu, D. D.,Approximation of functions by a new class of linear polynomial operators, Revue Roum. Math. Pures Appl.,13, pp. 1173–1194, 1969.

[5] Toader, S., A generalization of Polya distribution, Bull. Applied & Comput. Math.

(Budapest), 86A, pp. 477–484, 1998.

Received by the editors: November 19, 1999.

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